[tex]1\frac{1}{7} + 1 \frac{3}{6} [/tex]
[tex]12\frac{5}{6} - 7 \frac{3}{9} [/tex]
[tex]5 \frac{1}{3 } + \frac{3}{7} [/tex]
[tex]8 \frac{2}{9} - 4 \frac{2}{3} [/tex]
[tex]8 \frac{4}{14 } - 3 \frac{6}{7} [/tex]
[tex]4 \frac{7}{52} - 2 \frac{8}{13} [/tex]
berapa kak ? tolong pakek cara ya kak
Jawaban:
[tex]1\frac{1}{7} + 1 \frac{3}{6} \\ = ( 1 + 1) + ( \frac{1}{7} + \frac{3}{6} ) \\ = 2 + ( \frac{6}{42} + \frac{21}{42} ) \\ = 2 + \frac{27}{42} \\ = 2 \frac{27}{42} [/tex]
[tex]12\frac{5}{6} - 7 \frac{3}{9} \\ = \frac{77}{6} - \frac{66}{9} \\ = \frac{693}{54} - \frac{396}{54} \\ = \frac{297}{54} \\ = \frac{33}{6} \\ = 5 \frac{3}{6} [/tex]
[tex]5 \frac{1}{3 } + \frac{3}{7} \\ = \frac{16}{3} + \frac{3}{7} \\ = \frac{112}{21} + \frac{9}{21} \\ = \frac{121}{21} \\ = 5 \frac{16}{21} [/tex]
[tex]8 \frac{2}{9} - 4 \frac{2}{3} \\ = \frac{74}{9} - \frac{14}{3} \\ = \frac{74}{9} - \frac{42}{3} \\ = \frac{32}{3} \\ = 10 \frac{2}{3} [/tex]
[tex]8 \frac{4}{14 } - 3 \frac{6}{7} \\ = \frac{116}{14} - \frac{27}{7} \\ = \frac{116}{14} - \frac{54}{14} \\ = \frac{62}{14} \\ = \frac{31}{7} \\ = 4 \frac{3}{7} [/tex]
[tex]4 \frac{7}{52} - 2 \frac{8}{13} \\ = \frac{215}{52} - \frac{34}{13} \\ = \frac{215}{52} - \frac{136}{52} \\ = \frac{79}{52} \\ = 1 \frac{27}{52} [/tex]
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